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| "踏上LeetCode解題之路,順手紀錄一下PHP練功的過程囉。這是第十二篇~~" |
Best Time to Buy and Sell Stock - LeetCode
思考過程
待補上
結果✅
// 相減 找出利潤最大值
class Solution {
/**
* @param Integer[] $prices
* @return Integer
*/
function maxProfit(array $prices) {
$min= $prices[0];
$maxProfit = 0;
for ($i = 1; $i < count($prices); $i++) {
if ($min > $prices[$i]) {
$min = $prices[$i];
}
if ($maxProfit < ($prices[$i] - $min)) {
$maxProfit = $prices[$i] - $min;
}
}
return $maxProfit;
}
/**
* @param array $prices Stock prices array for each day.
* @return int the max profit possible in the market.
*/
function maxProfit(array $prices) {
$maxProfit = 0;
for ($i = 0; $i < count($prices); $i++) {
for($j = $i +1; $j < count($prices); $j++) {
if ($prices[$i] >= $prices[$j]) {
continue;
}
$diff = $prices[$j] - $prices[$i];
$maxProfit = $diff > $maxProfit ? $diff : $maxProfit;
}
}
return $maxProfit;
}
if ($buy > $maxProfit){
$maxProfit = $buy;
}
